Q.What is this link for? 
A.This page lists frequently asked questions and answers.

Q.Where can I read more about Dominey Model easily?
A.http://kona.usc.edu/HBP/models/conformant/Dominey_2.1/saccade_doc.html

Q.LANDMARK:I can't figure out how to use the nslRandom function to 
  generate a  random integer (-1, 1, 0).
A.You can always use java:use Math.random() instead...

Q. LANDMARK: I don't understand at all why your advising to use " The coordinates
> of the landmarks are: (0, 5), (0, -5), (5, 0), and (-5, 0)"
> According to the NSL reading the center would be at (20, 20) the East
> would be at (20, 40), North at (0, 20) at etc.
That is cool. Try to do it as the book says. If not you can try my suggestion..

Q. LANDMARK:> Can you explain the choice of coordinates?
it is arbitrary: you can get full mark using even (0,1000)x(0,1000)
The parameters I gave are the ones I used in my implementation. For me it is
more natural to have 0,0 origin. You are free to choose your own coordinate
system.                

Q. LANDMARK: The 'z' parameter: is that the measure of smellness: Smell(d) =
> 0.5*(1-d/r), if d<=r    or is it someother value?
No. Actually, the Xi values are the smells received from landmarks.
Z is decribed in chapter 12 of NSL book.                                  



Q. DEV: Several of us have the same question: what kind of formula I
should use to transform the information of dot position in the space to
disparity value we need for the simulation?        

A. Assume fixed positions for the three eyes and take the visual field
they see as a 2D grid. Then given a point on the grid you should be
able to compute the disparities in L-R eye and R-S eye system. 
You can program this process in initRun() methods to create the mappings
from visual (2d grid) field to disparity. 
Alternatively you can derive formula for the mappings.
Note that you may do simplifications in the "eye ball shape" for disparity
computations such as instead of having the arc length as the retinal
position you may use the half-chord length or you may assume a
triangular eye ball. But make sure that you are not oversimplyfing and
so loosing the main point!

Q. KOHONEN: Can you explain what ri ri* is?

A. ri is the position of the unit i in the network. In the homework your
units have linear topology. This means, ri is simply the index of unit i in
the array that you use to keep the units. ri* is the index of the winner unit.